Friday, August 29, 2014
As a practical matter, the price difference between copper and silver isn't so very great because the necklaces don't actually have that much metal in them. They're light as a feather. In fact, that may be a problem in some pieces down the road. On many of my copper pieces I used some 18mm melon shaped beads, mostly to add a little weight to make the piece hang better. But those same beads in silver are pretty pricey because they have a lot of silver in them. For now, the time it takes to cut and, more importantly, de-burr the cut tubes adds more to the cost of the work than the difference in metal prices. And I think silver has more customer appeal than copper.
The piece on top, with the tetrahelixes, was my first one with oxidized sterling. I find it doesn't oxidize as dark as the copper does, at least using liver of sulphur. There may be other chemicals that make it darker if I decide I want that. For now this is OK. I felt I needed seed beads at the ends of the aluminum tubes, so I used them at the ends of the
silver tubes too. On the second piece, below, I used them just on the aluminum, not on the silver. As I was cutting the silver, I found I was seduced by how pretty the bright silver was, so for the second piece, I left it bright (also the dark blue and purple show up better against the bright silver). However, as a practical matter, I don't want to spend a lot of time trying to clean silver, so I think I'll mostly darken it. I've looked at a lot of Flora Book's work with silver tubes, and it's so beautiful it tempts me to do more with bright silver. I'll just have to see as I go along.
On the bottom piece you can see the advantage of cutting my own tubes. It's a simple chain of octahedrons. But a chain of octahedrons would normally form a straight line. In order to get the curve you need for a necklace I had to make the triangle on the outside edge longer than the triangle on the inside edge.
Here's where some trig would have come in handy in figuring out just how much longer, but I managed to figure it out with "lesser" math, and it came out right.